If a ham radio tuner circuit has 5 resistors in parallel with the following values in ohms
4.2, 6.73, 15.2, 32, 66
then what is the total (R) resistance?
Solution
R = 1/(1/R1 + 1/R2 + 1/R3 + 1/R4 + 1/R5)
Answer
R = 1/(1/4.2 + 1/6.73 + 1/15.2 + 1/32 + 1/66)
R = 1/(.2381 + .148588 + .065789 + .03125 + .015151)
R = 1/(.498878)
R = 2.0045 ohms